Integrand size = 10, antiderivative size = 102 \[ \int \frac {\text {sech}^{-1}(a x)^2}{x^4} \, dx=-\frac {2}{27 x^3}-\frac {4 a^2}{9 x}+\frac {2 \sqrt {\frac {1-a x}{1+a x}} (1+a x) \text {sech}^{-1}(a x)}{9 x^3}+\frac {4 a^2 \sqrt {\frac {1-a x}{1+a x}} (1+a x) \text {sech}^{-1}(a x)}{9 x}-\frac {\text {sech}^{-1}(a x)^2}{3 x^3} \]
-2/27/x^3-4/9*a^2/x-1/3*arcsech(a*x)^2/x^3+2/9*(a*x+1)*arcsech(a*x)*((-a*x +1)/(a*x+1))^(1/2)/x^3+4/9*a^2*(a*x+1)*arcsech(a*x)*((-a*x+1)/(a*x+1))^(1/ 2)/x
Time = 0.11 (sec) , antiderivative size = 73, normalized size of antiderivative = 0.72 \[ \int \frac {\text {sech}^{-1}(a x)^2}{x^4} \, dx=\frac {-2 \left (1+6 a^2 x^2\right )+6 \sqrt {\frac {1-a x}{1+a x}} \left (1+a x+2 a^2 x^2+2 a^3 x^3\right ) \text {sech}^{-1}(a x)-9 \text {sech}^{-1}(a x)^2}{27 x^3} \]
(-2*(1 + 6*a^2*x^2) + 6*Sqrt[(1 - a*x)/(1 + a*x)]*(1 + a*x + 2*a^2*x^2 + 2 *a^3*x^3)*ArcSech[a*x] - 9*ArcSech[a*x]^2)/(27*x^3)
Time = 0.44 (sec) , antiderivative size = 121, normalized size of antiderivative = 1.19, number of steps used = 11, number of rules used = 10, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 1.000, Rules used = {6839, 5896, 3042, 3791, 3042, 3777, 26, 3042, 26, 3118}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {\text {sech}^{-1}(a x)^2}{x^4} \, dx\) |
\(\Big \downarrow \) 6839 |
\(\displaystyle -a^3 \int \frac {\sqrt {\frac {1-a x}{a x+1}} (a x+1) \text {sech}^{-1}(a x)^2}{a^3 x^3}d\text {sech}^{-1}(a x)\) |
\(\Big \downarrow \) 5896 |
\(\displaystyle -a^3 \left (\frac {\text {sech}^{-1}(a x)^2}{3 a^3 x^3}-\frac {2}{3} \int \frac {\text {sech}^{-1}(a x)}{a^3 x^3}d\text {sech}^{-1}(a x)\right )\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle -a^3 \left (\frac {\text {sech}^{-1}(a x)^2}{3 a^3 x^3}-\frac {2}{3} \int \text {sech}^{-1}(a x) \sin \left (i \text {sech}^{-1}(a x)+\frac {\pi }{2}\right )^3d\text {sech}^{-1}(a x)\right )\) |
\(\Big \downarrow \) 3791 |
\(\displaystyle -a^3 \left (\frac {\text {sech}^{-1}(a x)^2}{3 a^3 x^3}-\frac {2}{3} \left (\frac {2}{3} \int \frac {\text {sech}^{-1}(a x)}{a x}d\text {sech}^{-1}(a x)-\frac {1}{9 a^3 x^3}+\frac {\sqrt {\frac {1-a x}{a x+1}} (a x+1) \text {sech}^{-1}(a x)}{3 a^3 x^3}\right )\right )\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle -a^3 \left (\frac {\text {sech}^{-1}(a x)^2}{3 a^3 x^3}-\frac {2}{3} \left (\frac {2}{3} \int \text {sech}^{-1}(a x) \sin \left (i \text {sech}^{-1}(a x)+\frac {\pi }{2}\right )d\text {sech}^{-1}(a x)-\frac {1}{9 a^3 x^3}+\frac {\sqrt {\frac {1-a x}{a x+1}} (a x+1) \text {sech}^{-1}(a x)}{3 a^3 x^3}\right )\right )\) |
\(\Big \downarrow \) 3777 |
\(\displaystyle -a^3 \left (\frac {\text {sech}^{-1}(a x)^2}{3 a^3 x^3}-\frac {2}{3} \left (\frac {2}{3} \left (\frac {\sqrt {\frac {1-a x}{a x+1}} (a x+1) \text {sech}^{-1}(a x)}{a x}-i \int -\frac {i \sqrt {\frac {1-a x}{a x+1}} (a x+1)}{a x}d\text {sech}^{-1}(a x)\right )-\frac {1}{9 a^3 x^3}+\frac {\sqrt {\frac {1-a x}{a x+1}} (a x+1) \text {sech}^{-1}(a x)}{3 a^3 x^3}\right )\right )\) |
\(\Big \downarrow \) 26 |
\(\displaystyle -a^3 \left (\frac {\text {sech}^{-1}(a x)^2}{3 a^3 x^3}-\frac {2}{3} \left (\frac {2}{3} \left (\frac {\sqrt {\frac {1-a x}{a x+1}} (a x+1) \text {sech}^{-1}(a x)}{a x}-\int \frac {\sqrt {\frac {1-a x}{a x+1}} (a x+1)}{a x}d\text {sech}^{-1}(a x)\right )-\frac {1}{9 a^3 x^3}+\frac {\sqrt {\frac {1-a x}{a x+1}} (a x+1) \text {sech}^{-1}(a x)}{3 a^3 x^3}\right )\right )\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle -a^3 \left (\frac {\text {sech}^{-1}(a x)^2}{3 a^3 x^3}-\frac {2}{3} \left (\frac {2}{3} \left (\frac {\sqrt {\frac {1-a x}{a x+1}} (a x+1) \text {sech}^{-1}(a x)}{a x}-\int -i \sin \left (i \text {sech}^{-1}(a x)\right )d\text {sech}^{-1}(a x)\right )-\frac {1}{9 a^3 x^3}+\frac {\sqrt {\frac {1-a x}{a x+1}} (a x+1) \text {sech}^{-1}(a x)}{3 a^3 x^3}\right )\right )\) |
\(\Big \downarrow \) 26 |
\(\displaystyle -a^3 \left (\frac {\text {sech}^{-1}(a x)^2}{3 a^3 x^3}-\frac {2}{3} \left (\frac {2}{3} \left (\frac {\sqrt {\frac {1-a x}{a x+1}} (a x+1) \text {sech}^{-1}(a x)}{a x}+i \int \sin \left (i \text {sech}^{-1}(a x)\right )d\text {sech}^{-1}(a x)\right )-\frac {1}{9 a^3 x^3}+\frac {\sqrt {\frac {1-a x}{a x+1}} (a x+1) \text {sech}^{-1}(a x)}{3 a^3 x^3}\right )\right )\) |
\(\Big \downarrow \) 3118 |
\(\displaystyle -a^3 \left (\frac {\text {sech}^{-1}(a x)^2}{3 a^3 x^3}-\frac {2}{3} \left (-\frac {1}{9 a^3 x^3}+\frac {\sqrt {\frac {1-a x}{a x+1}} (a x+1) \text {sech}^{-1}(a x)}{3 a^3 x^3}+\frac {2}{3} \left (\frac {\sqrt {\frac {1-a x}{a x+1}} (a x+1) \text {sech}^{-1}(a x)}{a x}-\frac {1}{a x}\right )\right )\right )\) |
-(a^3*(ArcSech[a*x]^2/(3*a^3*x^3) - (2*(-1/9*1/(a^3*x^3) + (Sqrt[(1 - a*x) /(1 + a*x)]*(1 + a*x)*ArcSech[a*x])/(3*a^3*x^3) + (2*(-(1/(a*x)) + (Sqrt[( 1 - a*x)/(1 + a*x)]*(1 + a*x)*ArcSech[a*x])/(a*x)))/3))/3))
3.1.9.3.1 Defintions of rubi rules used
Int[(Complex[0, a_])*(Fx_), x_Symbol] :> Simp[(Complex[Identity[0], a]) I nt[Fx, x], x] /; FreeQ[a, x] && EqQ[a^2, 1]
Int[((c_.) + (d_.)*(x_))^(m_.)*sin[(e_.) + (f_.)*(x_)], x_Symbol] :> Simp[( -(c + d*x)^m)*(Cos[e + f*x]/f), x] + Simp[d*(m/f) Int[(c + d*x)^(m - 1)*C os[e + f*x], x], x] /; FreeQ[{c, d, e, f}, x] && GtQ[m, 0]
Int[((c_.) + (d_.)*(x_))*((b_.)*sin[(e_.) + (f_.)*(x_)])^(n_), x_Symbol] :> Simp[d*((b*Sin[e + f*x])^n/(f^2*n^2)), x] + (-Simp[b*(c + d*x)*Cos[e + f*x ]*((b*Sin[e + f*x])^(n - 1)/(f*n)), x] + Simp[b^2*((n - 1)/n) Int[(c + d* x)*(b*Sin[e + f*x])^(n - 2), x], x]) /; FreeQ[{b, c, d, e, f}, x] && GtQ[n, 1]
Int[Cosh[(a_.) + (b_.)*(x_)^(n_.)]^(p_.)*(x_)^(m_.)*Sinh[(a_.) + (b_.)*(x_) ^(n_.)], x_Symbol] :> Simp[x^(m - n + 1)*(Cosh[a + b*x^n]^(p + 1)/(b*n*(p + 1))), x] - Simp[(m - n + 1)/(b*n*(p + 1)) Int[x^(m - n)*Cosh[a + b*x^n]^ (p + 1), x], x] /; FreeQ[{a, b, p}, x] && LtQ[0, n, m + 1] && NeQ[p, -1]
Int[((a_.) + ArcSech[(c_.)*(x_)]*(b_.))^(n_)*(x_)^(m_.), x_Symbol] :> Simp[ -(c^(m + 1))^(-1) Subst[Int[(a + b*x)^n*Sech[x]^(m + 1)*Tanh[x], x], x, A rcSech[c*x]], x] /; FreeQ[{a, b, c}, x] && IntegerQ[n] && IntegerQ[m] && (G tQ[n, 0] || LtQ[m, -1])
Time = 0.83 (sec) , antiderivative size = 112, normalized size of antiderivative = 1.10
method | result | size |
derivativedivides | \(a^{3} \left (-\frac {\operatorname {arcsech}\left (a x \right )^{2}}{3 a^{3} x^{3}}+\frac {4 \sqrt {-\frac {a x -1}{a x}}\, \sqrt {\frac {a x +1}{a x}}\, \operatorname {arcsech}\left (a x \right )}{9}+\frac {2 \sqrt {-\frac {a x -1}{a x}}\, \sqrt {\frac {a x +1}{a x}}\, \operatorname {arcsech}\left (a x \right )}{9 a^{2} x^{2}}-\frac {4}{9 a x}-\frac {2}{27 x^{3} a^{3}}\right )\) | \(112\) |
default | \(a^{3} \left (-\frac {\operatorname {arcsech}\left (a x \right )^{2}}{3 a^{3} x^{3}}+\frac {4 \sqrt {-\frac {a x -1}{a x}}\, \sqrt {\frac {a x +1}{a x}}\, \operatorname {arcsech}\left (a x \right )}{9}+\frac {2 \sqrt {-\frac {a x -1}{a x}}\, \sqrt {\frac {a x +1}{a x}}\, \operatorname {arcsech}\left (a x \right )}{9 a^{2} x^{2}}-\frac {4}{9 a x}-\frac {2}{27 x^{3} a^{3}}\right )\) | \(112\) |
a^3*(-1/3/a^3/x^3*arcsech(a*x)^2+4/9*(-(a*x-1)/a/x)^(1/2)*((a*x+1)/a/x)^(1 /2)*arcsech(a*x)+2/9/a^2/x^2*(-(a*x-1)/a/x)^(1/2)*((a*x+1)/a/x)^(1/2)*arcs ech(a*x)-4/9/a/x-2/27/x^3/a^3)
Time = 0.25 (sec) , antiderivative size = 116, normalized size of antiderivative = 1.14 \[ \int \frac {\text {sech}^{-1}(a x)^2}{x^4} \, dx=-\frac {12 \, a^{2} x^{2} - 6 \, {\left (2 \, a^{3} x^{3} + a x\right )} \sqrt {-\frac {a^{2} x^{2} - 1}{a^{2} x^{2}}} \log \left (\frac {a x \sqrt {-\frac {a^{2} x^{2} - 1}{a^{2} x^{2}}} + 1}{a x}\right ) + 9 \, \log \left (\frac {a x \sqrt {-\frac {a^{2} x^{2} - 1}{a^{2} x^{2}}} + 1}{a x}\right )^{2} + 2}{27 \, x^{3}} \]
-1/27*(12*a^2*x^2 - 6*(2*a^3*x^3 + a*x)*sqrt(-(a^2*x^2 - 1)/(a^2*x^2))*log ((a*x*sqrt(-(a^2*x^2 - 1)/(a^2*x^2)) + 1)/(a*x)) + 9*log((a*x*sqrt(-(a^2*x ^2 - 1)/(a^2*x^2)) + 1)/(a*x))^2 + 2)/x^3
\[ \int \frac {\text {sech}^{-1}(a x)^2}{x^4} \, dx=\int \frac {\operatorname {asech}^{2}{\left (a x \right )}}{x^{4}}\, dx \]
\[ \int \frac {\text {sech}^{-1}(a x)^2}{x^4} \, dx=\int { \frac {\operatorname {arsech}\left (a x\right )^{2}}{x^{4}} \,d x } \]
\[ \int \frac {\text {sech}^{-1}(a x)^2}{x^4} \, dx=\int { \frac {\operatorname {arsech}\left (a x\right )^{2}}{x^{4}} \,d x } \]
Timed out. \[ \int \frac {\text {sech}^{-1}(a x)^2}{x^4} \, dx=\int \frac {{\mathrm {acosh}\left (\frac {1}{a\,x}\right )}^2}{x^4} \,d x \]